-5y-5(4y-2)=2-5(-8-y)

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Solution for -5y-5(4y-2)=2-5(-8-y) equation: 



-5y-5(4y-2)=2-5(-8-y)

We move all terms to the left:

-5y-5(4y-2)-(2-5(-8-y))=0

We add all the numbers together, and all the variables

-5y-5(4y-2)-(2-5(-1y-8))=0

We multiply parentheses

-5y-20y-(2-5(-1y-8))+10=0



We calculate terms in parentheses: -(2-5(-1y-8)), so:

2-5(-1y-8)

determiningTheFunctionDomain
-5(-1y-8)+2

We multiply parentheses

5y+40+2

We add all the numbers together, and all the variables

5y+42

Back to the equation:

-(5y+42)



We add all the numbers together, and all the variables

-25y-(5y+42)+10=0

We get rid of parentheses

-25y-5y-42+10=0

We add all the numbers together, and all the variables

-30y-32=0

We move all terms containing y to the left, all other terms to the right

-30y=32

y=32/-30

y=-1+1/15

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