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3x-13=7x(x+2)-4(x-7)
We move all terms to the left:
3x-13-(7x(x+2)-4(x-7))=0
We calculate terms in parentheses: -(7x(x+2)-4(x-7)), so:We get rid of parentheses
7x(x+2)-4(x-7)
We multiply parentheses
7x^2+14x-4x+28
We add all the numbers together, and all the variables
7x^2+10x+28
Back to the equation:
-(7x^2+10x+28)
-7x^2+3x-10x-28-13=0
We add all the numbers together, and all the variables
-7x^2-7x-41=0
a = -7; b = -7; c = -41;
Δ = b2-4ac
Δ = -72-4·(-7)·(-41)
Δ = -1099
Delta is less than zero, so there is no solution for the equation
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