-5y+2(-3y-5)=-3-7(2-y)

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Solution for -5y+2(-3y-5)=-3-7(2-y) equation: 



-5y+2(-3y-5)=-3-7(2-y)

We move all terms to the left:

-5y+2(-3y-5)-(-3-7(2-y))=0

We add all the numbers together, and all the variables

-5y+2(-3y-5)-(-3-7(-1y+2))=0

We multiply parentheses

-5y-6y-(-3-7(-1y+2))-10=0



We calculate terms in parentheses: -(-3-7(-1y+2)), so:

-3-7(-1y+2)

determiningTheFunctionDomain
-7(-1y+2)-3

We multiply parentheses

7y-14-3

We add all the numbers together, and all the variables

7y-17

Back to the equation:

-(7y-17)



We add all the numbers together, and all the variables

-11y-(7y-17)-10=0

We get rid of parentheses

-11y-7y+17-10=0

We add all the numbers together, and all the variables

-18y+7=0

We move all terms containing y to the left, all other terms to the right

-18y=-7

y=-7/-18

y=7/18

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