F(z)=242z-34+1z

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Solution for F(z)=242z-34+1z equation: 



(F)=242F-34+1F

We move all terms to the left:

(F)-(242F-34+1F)=0

We add all the numbers together, and all the variables

F-(243F-34)=0

We get rid of parentheses

F-243F+34=0

We add all the numbers together, and all the variables

-242F+34=0

We move all terms containing F to the left, all other terms to the right

-242F=-34

F=-34/-242

F=17/121

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