-5x(3x+5)=7x(3x-4)+27

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Solution for -5x(3x+5)=7x(3x-4)+27 equation: 



-5x(3x+5)=7x(3x-4)+27

We move all terms to the left:

-5x(3x+5)-(7x(3x-4)+27)=0

We multiply parentheses

-15x^2-25x-(7x(3x-4)+27)=0



We calculate terms in parentheses: -(7x(3x-4)+27), so:

7x(3x-4)+27

We multiply parentheses

21x^2-28x+27

Back to the equation:

-(21x^2-28x+27)



We get rid of parentheses

-15x^2-21x^2-25x+28x-27=0

We add all the numbers together, and all the variables

-36x^2+3x-27=0

a = -36; b = 3; c = -27;
Δ = b2-4ac
Δ = 32-4·(-36)·(-27)
Δ = -3879
Delta is less than zero, so there is no solution for the equation

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