3+6(n-4)=51

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Solution for 3+6(n-4)=51 equation: 



3+6(n-4)=51

We move all terms to the left:

3+6(n-4)-(51)=0

We add all the numbers together, and all the variables

6(n-4)-48=0

We multiply parentheses

6n-24-48=0

We add all the numbers together, and all the variables

6n-72=0

We move all terms containing n to the left, all other terms to the right

6n=72

n=72/6

n=12

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