-5x(-1x+10)+20=10

Solution for -5x(-1x+10)+20=10 equation:

-5x(-1x+10)+20=10

We move all terms to the left:

-5x(-1x+10)+20-(10)=0

We add all the numbers together, and all the variables

-5x(-1x+10)+10=0

We multiply parentheses

5x^2-50x+10=0

a = 5; b = -50; c = +10;
Δ = b2-4ac
Δ = -502-4·5·10
Δ = 2300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2300}=\sqrt{100*23}=\sqrt{100}*\sqrt{23}=10\sqrt{23}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-10\sqrt{23}}{2*5}=\frac{50-10\sqrt{23}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+10\sqrt{23}}{2*5}=\frac{50+10\sqrt{23}}{10}
$