23=12(2z-6)

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Solution for 23=12(2z-6) equation: 



23=12(2z-6)

We move all terms to the left:

23-(12(2z-6))=0



We calculate terms in parentheses: -(12(2z-6)), so:

12(2z-6)

We multiply parentheses

24z-72

Back to the equation:

-(24z-72)



We get rid of parentheses

-24z+72+23=0

We add all the numbers together, and all the variables

-24z+95=0

We move all terms containing z to the left, all other terms to the right

-24z=-95

z=-95/-24

z=3+23/24

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