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-5t^2+70t=0
a = -5; b = 70; c = 0;
Δ = b2-4ac
Δ = 702-4·(-5)·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-70}{2*-5}=\frac{-140}{-10} =+14 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+70}{2*-5}=\frac{0}{-10} =0 $
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