0=-5t(t-14)

Solution for 0=-5t(t-14) equation:

0=-5t(t-14)

We move all terms to the left:

0-(-5t(t-14))=0

We add all the numbers together, and all the variables

-(-5t(t-14))=0


We calculate terms in parentheses: -(-5t(t-14)), so:

-5t(t-14)

We multiply parentheses

-5t^2+70t

Back to the equation:

-(-5t^2+70t)


We get rid of parentheses

5t^2-70t=0

a = 5; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·5·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*5}=\frac{0}{10}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*5}=\frac{140}{10}
=14
$