-5e2-4e=-33

Solution for -5e2-4e=-33 equation:

-5e^2-4e=-33

We move all terms to the left:

-5e^2-4e-(-33)=0

We add all the numbers together, and all the variables

-5e^2-4e+33=0

a = -5; b = -4; c = +33;
Δ = b2-4ac
Δ = -42-4·(-5)·33
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-26}{2*-5}=\frac{-22}{-10}
=2+1/5
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+26}{2*-5}=\frac{30}{-10}
=-3
$