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-576x^2+225024x-9376=0
a = -576; b = 225024; c = -9376;
Δ = b2-4ac
Δ = 2250242-4·(-576)·(-9376)
Δ = 50614198272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{50614198272}=\sqrt{36864*1372998}=\sqrt{36864}*\sqrt{1372998}=192\sqrt{1372998}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(225024)-192\sqrt{1372998}}{2*-576}=\frac{-225024-192\sqrt{1372998}}{-1152} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(225024)+192\sqrt{1372998}}{2*-576}=\frac{-225024+192\sqrt{1372998}}{-1152} $
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