1/9(4x-32)=1/3(4x+8)

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Solution for 1/9(4x-32)=1/3(4x+8) equation: 



1/9(4x-32)=1/3(4x+8)

We move all terms to the left:

1/9(4x-32)-(1/3(4x+8))=0



Domain of the equation: 9(4x-32)!=0

x∈R





Domain of the equation: 3(4x+8))!=0

x∈R



We calculate fractions


(3x4/(9(4x-32)*3(4x+8)))+(-9x4/(9(4x-32)*3(4x+8)))=0



We calculate terms in parentheses: +(3x4/(9(4x-32)*3(4x+8))), so:

3x4/(9(4x-32)*3(4x+8))

We multiply all the terms by the denominator


3x4

We add all the numbers together, and all the variables

3x^4

We do not support expression: x^4

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