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-53+3x+8=9(x-5)-6x
We move all terms to the left:
-53+3x+8-(9(x-5)-6x)=0
We add all the numbers together, and all the variables
3x-(9(x-5)-6x)-45=0
We calculate terms in parentheses: -(9(x-5)-6x), so:We get rid of parentheses
9(x-5)-6x
We add all the numbers together, and all the variables
-6x+9(x-5)
We multiply parentheses
-6x+9x-45
We add all the numbers together, and all the variables
3x-45
Back to the equation:
-(3x-45)
3x-3x+45-45=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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