(2x/5x)+x=58578

Solution for (2x/5x)+x=58578 equation:

(2x/5x)+x=58578

We move all terms to the left:

(2x/5x)+x-(58578)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2x/5x)+x-58578=0

We add all the numbers together, and all the variables

x+(+2x/5x)-58578=0

We get rid of parentheses

x+2x/5x-58578=0

We multiply all the terms by the denominator


x*5x+2x-58578*5x=0

We add all the numbers together, and all the variables

2x+x*5x-58578*5x=0

Wy multiply elements

5x^2+2x-292890x=0

We add all the numbers together, and all the variables

5x^2-292888x=0

a = 5; b = -292888; c = 0;
Δ = b2-4ac
Δ = -2928882-4·5·0
Δ = 85783380544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{85783380544}=292888$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-292888)-292888}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-292888)+292888}{2*5}=\frac{585776}{10}
=58577+3/5
$