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-5/x1=5/x-3
We move all terms to the left:
-5/x1-(5/x-3)=0
Domain of the equation: x1!=0
x^1!=0/
x^1!=√0
x!=0
x∈R
Domain of the equation: x-3)!=0We get rid of parentheses
x∈R
-5/x1-5/x+3=0
We calculate fractions
(-5x)/x^2+(-5x)/x^2+3=0
We multiply all the terms by the denominator
(-5x)+(-5x)+3*x^2=0
We add all the numbers together, and all the variables
3x^2+(-5x)+(-5x)=0
We get rid of parentheses
3x^2-5x-5x=0
We add all the numbers together, and all the variables
3x^2-10x=0
a = 3; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·3·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*3}=\frac{20}{6} =3+1/3 $
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