(40-x/3)+x=40

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Solution for (40-x/3)+x=40 equation: 



(40-x/3)+x=40

We move all terms to the left:

(40-x/3)+x-(40)=0

We add all the numbers together, and all the variables

(-x/3+40)+x-40=0

We add all the numbers together, and all the variables

x+(-x/3+40)-40=0

We get rid of parentheses

x-x/3+40-40=0

We multiply all the terms by the denominator


x*3-x+40*3-40*3=0

We add all the numbers together, and all the variables

-1x+x*3=0

Wy multiply elements

-1x+3x=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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