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-5/6x-1/9x=-1
We move all terms to the left:
-5/6x-1/9x-(-1)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
-5/6x-1/9x+1=0
We calculate fractions
(-45x)/54x^2+(-6x)/54x^2+1=0
We multiply all the terms by the denominator
(-45x)+(-6x)+1*54x^2=0
Wy multiply elements
54x^2+(-45x)+(-6x)=0
We get rid of parentheses
54x^2-45x-6x=0
We add all the numbers together, and all the variables
54x^2-51x=0
a = 54; b = -51; c = 0;
Δ = b2-4ac
Δ = -512-4·54·0
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-51}{2*54}=\frac{0}{108} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+51}{2*54}=\frac{102}{108} =17/18 $
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