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-5/10x=8x+9
We move all terms to the left:
-5/10x-(8x+9)=0
Domain of the equation: 10x!=0We get rid of parentheses
x!=0/10
x!=0
x∈R
-5/10x-8x-9=0
We multiply all the terms by the denominator
-8x*10x-9*10x-5=0
Wy multiply elements
-80x^2-90x-5=0
a = -80; b = -90; c = -5;
Δ = b2-4ac
Δ = -902-4·(-80)·(-5)
Δ = 6500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6500}=\sqrt{100*65}=\sqrt{100}*\sqrt{65}=10\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-10\sqrt{65}}{2*-80}=\frac{90-10\sqrt{65}}{-160} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+10\sqrt{65}}{2*-80}=\frac{90+10\sqrt{65}}{-160} $
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