3x2-5x-4+-16=(2-16+2x2)

Solution for 3x2-5x-4+-16=(2-16+2x2) equation:

3x^2-5x-4+-16=(2-16+2x^2)

We move all terms to the left:

3x^2-5x-4+-16-((2-16+2x^2))=0

We add all the numbers together, and all the variables

3x^2-((2-16+2x^2))-5x=0


We calculate terms in parentheses: -((2-16+2x^2)), so:

(2-16+2x^2)

We get rid of parentheses

2x^2+2-16

We add all the numbers together, and all the variables

2x^2-14

Back to the equation:

-(2x^2-14)


We add all the numbers together, and all the variables

3x^2-5x-(2x^2-14)=0

We get rid of parentheses

3x^2-2x^2-5x+14=0

We add all the numbers together, and all the variables

x^2-5x+14=0

a = 1; b = -5; c = +14;
Δ = b2-4ac
Δ = -52-4·1·14
Δ = -31
Delta is less than zero, so there is no solution for the equation