-5(z-7)=30-(2z+1)

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Solution for -5(z-7)=30-(2z+1) equation: 



-5(z-7)=30-(2z+1)

We move all terms to the left:

-5(z-7)-(30-(2z+1))=0

We multiply parentheses

-5z-(30-(2z+1))+35=0



We calculate terms in parentheses: -(30-(2z+1)), so:

30-(2z+1)

determiningTheFunctionDomain
-(2z+1)+30

We get rid of parentheses

-2z-1+30

We add all the numbers together, and all the variables

-2z+29

Back to the equation:

-(-2z+29)



We get rid of parentheses

-5z+2z-29+35=0

We add all the numbers together, and all the variables

-3z+6=0

We move all terms containing z to the left, all other terms to the right

-3z=-6

z=-6/-3

z=+2

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