5(z-7)=30(2z+1)

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Solution for 5(z-7)=30(2z+1) equation: 



5(z-7)=30(2z+1)

We move all terms to the left:

5(z-7)-(30(2z+1))=0

We multiply parentheses

5z-(30(2z+1))-35=0



We calculate terms in parentheses: -(30(2z+1)), so:

30(2z+1)

We multiply parentheses

60z+30

Back to the equation:

-(60z+30)



We get rid of parentheses

5z-60z-30-35=0

We add all the numbers together, and all the variables

-55z-65=0

We move all terms containing z to the left, all other terms to the right

-55z=65

z=65/-55

z=-1+2/11

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