-5(z-25)=2/5(z+30)

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Solution for -5(z-25)=2/5(z+30) equation: 



-5(z-25)=2/5(z+30)

We move all terms to the left:

-5(z-25)-(2/5(z+30))=0



Domain of the equation: 5(z+30))!=0

z∈R



We multiply parentheses

-5z-(2/5(z+30))+125=0

We multiply all the terms by the denominator


-5z*5(z+30))-(2+125*5(z+30))=0

Wy multiply elements

-25z^2(z+625z(z=0

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