(6x+38)=(3x+70)

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Solution for (6x+38)=(3x+70) equation: 



(6x+38)=(3x+70)

We move all terms to the left:

(6x+38)-((3x+70))=0

We get rid of parentheses

6x-((3x+70))+38=0



We calculate terms in parentheses: -((3x+70)), so:

(3x+70)

We get rid of parentheses

3x+70

Back to the equation:

-(3x+70)



We get rid of parentheses

6x-3x-70+38=0

We add all the numbers together, and all the variables

3x-32=0

We move all terms containing x to the left, all other terms to the right

3x=32

x=32/3

x=10+2/3

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