-5(y-4y)+5=-4(2y-y)+2+18y

Solution for -5(y-4y)+5=-4(2y-y)+2+18y equation:

-5(y-4y)+5=-4(2y-y)+2+18y

We move all terms to the left:

-5(y-4y)+5-(-4(2y-y)+2+18y)=0

We add all the numbers together, and all the variables

-5(-3y)-(-4(+y)+2+18y)+5=0

We multiply parentheses

15y-(-4(+y)+2+18y)+5=0


We calculate terms in parentheses: -(-4(+y)+2+18y), so:

-4(+y)+2+18y

determiningTheFunctionDomain
-4(+y)+18y+2

We add all the numbers together, and all the variables

18y-4(+y)+2

We multiply parentheses

18y-4y+2

We add all the numbers together, and all the variables

14y+2

Back to the equation:

-(14y+2)


We get rid of parentheses

15y-14y-2+5=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3