(2+2x)=16-2(-2+x)

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Solution for (2+2x)=16-2(-2+x) equation: 



(2+2x)=16-2(-2+x)

We move all terms to the left:

(2+2x)-(16-2(-2+x))=0

We add all the numbers together, and all the variables

(2x+2)-(16-2(x-2))=0

We get rid of parentheses

2x-(16-2(x-2))+2=0



We calculate terms in parentheses: -(16-2(x-2)), so:

16-2(x-2)

determiningTheFunctionDomain
-2(x-2)+16

We multiply parentheses

-2x+4+16

We add all the numbers together, and all the variables

-2x+20

Back to the equation:

-(-2x+20)



We get rid of parentheses

2x+2x-20+2=0

We add all the numbers together, and all the variables

4x-18=0

We move all terms containing x to the left, all other terms to the right

4x=18

x=18/4

x=4+1/2

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