-5(y-2y)+9=-3(6y-y)+6+19y

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Solution for -5(y-2y)+9=-3(6y-y)+6+19y equation: 



-5(y-2y)+9=-3(6y-y)+6+19y

We move all terms to the left:

-5(y-2y)+9-(-3(6y-y)+6+19y)=0

We add all the numbers together, and all the variables

-5(-1y)-(-3(+5y)+6+19y)+9=0

We multiply parentheses

5y-(-3(+5y)+6+19y)+9=0



We calculate terms in parentheses: -(-3(+5y)+6+19y), so:

-3(+5y)+6+19y

determiningTheFunctionDomain
-3(+5y)+19y+6

We add all the numbers together, and all the variables

19y-3(+5y)+6

We multiply parentheses

19y-15y+6

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)



We get rid of parentheses

5y-4y-6+9=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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