-5(y-2y)+4=-6(3y+y)+3+16y

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Solution for -5(y-2y)+4=-6(3y+y)+3+16y equation: 



-5(y-2y)+4=-6(3y+y)+3+16y

We move all terms to the left:

-5(y-2y)+4-(-6(3y+y)+3+16y)=0

We add all the numbers together, and all the variables

-5(-1y)-(-6(+4y)+3+16y)+4=0

We multiply parentheses

5y-(-6(+4y)+3+16y)+4=0



We calculate terms in parentheses: -(-6(+4y)+3+16y), so:

-6(+4y)+3+16y

determiningTheFunctionDomain
-6(+4y)+16y+3

We add all the numbers together, and all the variables

16y-6(+4y)+3

We multiply parentheses

16y-24y+3

We add all the numbers together, and all the variables

-8y+3

Back to the equation:

-(-8y+3)



We get rid of parentheses

5y+8y-3+4=0

We add all the numbers together, and all the variables

13y+1=0

We move all terms containing y to the left, all other terms to the right

13y=-1

y=-1/13

y=-1/13

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