-5(y+2)=8y-4

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Solution for -5(y+2)=8y-4 equation: 



-5(y+2)=8y-4

We move all terms to the left:

-5(y+2)-(8y-4)=0

We multiply parentheses

-5y-(8y-4)-10=0

We get rid of parentheses

-5y-8y+4-10=0

We add all the numbers together, and all the variables

-13y-6=0

We move all terms containing y to the left, all other terms to the right

-13y=6

y=6/-13

y=-6/13

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