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5x^2-44x+120=-30+11x
We move all terms to the left:
5x^2-44x+120-(-30+11x)=0
We add all the numbers together, and all the variables
5x^2-44x-(11x-30)+120=0
We get rid of parentheses
5x^2-44x-11x+30+120=0
We add all the numbers together, and all the variables
5x^2-55x+150=0
a = 5; b = -55; c = +150;
Δ = b2-4ac
Δ = -552-4·5·150
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-5}{2*5}=\frac{50}{10} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+5}{2*5}=\frac{60}{10} =6 $
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