-5(x-3)+8x=2(x-10)+35

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Solution for -5(x-3)+8x=2(x-10)+35 equation:



-5(x-3)+8x=2(x-10)+35
We move all terms to the left:
-5(x-3)+8x-(2(x-10)+35)=0
We add all the numbers together, and all the variables
8x-5(x-3)-(2(x-10)+35)=0
We multiply parentheses
8x-5x-(2(x-10)+35)+15=0
We calculate terms in parentheses: -(2(x-10)+35), so:
2(x-10)+35
We multiply parentheses
2x-20+35
We add all the numbers together, and all the variables
2x+15
Back to the equation:
-(2x+15)
We add all the numbers together, and all the variables
3x-(2x+15)+15=0
We get rid of parentheses
3x-2x-15+15=0
We add all the numbers together, and all the variables
x=0

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