-5(x-3)+7(x+1)=4(x-2)-6

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Solution for -5(x-3)+7(x+1)=4(x-2)-6 equation: 



-5(x-3)+7(x+1)=4(x-2)-6

We move all terms to the left:

-5(x-3)+7(x+1)-(4(x-2)-6)=0

We multiply parentheses

-5x+7x-(4(x-2)-6)+15+7=0



We calculate terms in parentheses: -(4(x-2)-6), so:

4(x-2)-6

We multiply parentheses

4x-8-6

We add all the numbers together, and all the variables

4x-14

Back to the equation:

-(4x-14)



We add all the numbers together, and all the variables

2x-(4x-14)+22=0

We get rid of parentheses

2x-4x+14+22=0

We add all the numbers together, and all the variables

-2x+36=0

We move all terms containing x to the left, all other terms to the right

-2x=-36

x=-36/-2

x=+18

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