(1-w)(3w+7)=0

Solution for (1-w)(3w+7)=0 equation:

(1-w)(3w+7)=0

We add all the numbers together, and all the variables

(-1w+1)(3w+7)=0

We multiply parentheses ..

(-3w^2-7w+3w+7)=0

We get rid of parentheses

-3w^2-7w+3w+7=0

We add all the numbers together, and all the variables

-3w^2-4w+7=0

a = -3; b = -4; c = +7;
Δ = b2-4ac
Δ = -42-4·(-3)·7
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-10}{2*-3}=\frac{-6}{-6}
=1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+10}{2*-3}=\frac{14}{-6}
=-2+1/3
$