-5(x-2)/3=(2-8x)/6

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Solution for -5(x-2)/3=(2-8x)/6 equation: 



-5(x-2)/3=(2-8x)/6

We move all terms to the left:

-5(x-2)/3-((2-8x)/6)=0

We add all the numbers together, and all the variables

-5(x-2)/3-((-8x+2)/6)=0

We calculate fractions


(-5x)/()+(-((-8x+2)*3)/()=0



We calculate terms in parentheses: +(-((-8x+2)*3)/(), so:

-((-8x+2)*3)/(

We multiply all the terms by the denominator


-((-8x+2)*3)



We calculate terms in parentheses: -((-8x+2)*3), so:

(-8x+2)*3

We multiply parentheses

-24x+6

Back to the equation:

-(-24x+6)



We get rid of parentheses

24x-6

Back to the equation:

+(24x-6)



We get rid of parentheses

(-5x)/()+24x-6=0

We multiply all the terms by the denominator


(-5x)+24x*()-6*()=0

We add all the numbers together, and all the variables

(-5x)+24x*()=0

We get rid of parentheses

-5x+24x*()=0

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