(2x-8/2)+7=(x+7/7)+8

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Solution for (2x-8/2)+7=(x+7/7)+8 equation: 



(2x-8/2)+7=(x+7/7)+8

We move all terms to the left:

(2x-8/2)+7-((x+7/7)+8)=0

We add all the numbers together, and all the variables

(2x-4)-((x+1)+8)+7=0

We get rid of parentheses

2x-((x+1)+8)-4+7=0



We calculate terms in parentheses: -((x+1)+8), so:

(x+1)+8

We get rid of parentheses

x+1+8

We add all the numbers together, and all the variables

x+9

Back to the equation:

-(x+9)



We add all the numbers together, and all the variables

2x-(x+9)+3=0

We get rid of parentheses

2x-x-9+3=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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