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-5(v+2)=7v-2+2(2v+5)
We move all terms to the left:
-5(v+2)-(7v-2+2(2v+5))=0
We multiply parentheses
-5v-(7v-2+2(2v+5))-10=0
We calculate terms in parentheses: -(7v-2+2(2v+5)), so:We get rid of parentheses
7v-2+2(2v+5)
determiningTheFunctionDomain 7v+2(2v+5)-2
We multiply parentheses
7v+4v+10-2
We add all the numbers together, and all the variables
11v+8
Back to the equation:
-(11v+8)
-5v-11v-8-10=0
We add all the numbers together, and all the variables
-16v-18=0
We move all terms containing v to the left, all other terms to the right
-16v=18
v=18/-16
v=-1+1/8
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