4(y-1)=2y+8-2(-6y-1)

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Solution for 4(y-1)=2y+8-2(-6y-1) equation: 



4(y-1)=2y+8-2(-6y-1)

We move all terms to the left:

4(y-1)-(2y+8-2(-6y-1))=0

We multiply parentheses

4y-(2y+8-2(-6y-1))-4=0



We calculate terms in parentheses: -(2y+8-2(-6y-1)), so:

2y+8-2(-6y-1)

determiningTheFunctionDomain
2y-2(-6y-1)+8

We multiply parentheses

2y+12y+2+8

We add all the numbers together, and all the variables

14y+10

Back to the equation:

-(14y+10)



We get rid of parentheses

4y-14y-10-4=0

We add all the numbers together, and all the variables

-10y-14=0

We move all terms containing y to the left, all other terms to the right

-10y=14

y=14/-10

y=-1+2/5

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