-5(u+2)=u-7+3(2u+4)

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Solution for -5(u+2)=u-7+3(2u+4) equation: 



-5(u+2)=u-7+3(2u+4)

We move all terms to the left:

-5(u+2)-(u-7+3(2u+4))=0

We multiply parentheses

-5u-(u-7+3(2u+4))-10=0



We calculate terms in parentheses: -(u-7+3(2u+4)), so:

u-7+3(2u+4)

determiningTheFunctionDomain
u+3(2u+4)-7

We multiply parentheses

u+6u+12-7

We add all the numbers together, and all the variables

7u+5

Back to the equation:

-(7u+5)



We get rid of parentheses

-5u-7u-5-10=0

We add all the numbers together, and all the variables

-12u-15=0

We move all terms containing u to the left, all other terms to the right

-12u=15

u=15/-12

u=-1+1/4

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