2(x+2)=-6(3x-1)+8x

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Solution for 2(x+2)=-6(3x-1)+8x equation: 



2(x+2)=-6(3x-1)+8x

We move all terms to the left:

2(x+2)-(-6(3x-1)+8x)=0

We multiply parentheses

2x-(-6(3x-1)+8x)+4=0



We calculate terms in parentheses: -(-6(3x-1)+8x), so:

-6(3x-1)+8x

We add all the numbers together, and all the variables

8x-6(3x-1)

We multiply parentheses

8x-18x+6

We add all the numbers together, and all the variables

-10x+6

Back to the equation:

-(-10x+6)



We get rid of parentheses

2x+10x-6+4=0

We add all the numbers together, and all the variables

12x-2=0

We move all terms containing x to the left, all other terms to the right

12x=2

x=2/12

x=1/6

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