-5(t+4)-4(-2t-7)=2(t+2)-7

Solution for -5(t+4)-4(-2t-7)=2(t+2)-7 equation:

-5(t+4)-4(-2t-7)=2(t+2)-7

We move all terms to the left:

-5(t+4)-4(-2t-7)-(2(t+2)-7)=0

We multiply parentheses

-5t+8t-(2(t+2)-7)-20+28=0


We calculate terms in parentheses: -(2(t+2)-7), so:

2(t+2)-7

We multiply parentheses

2t+4-7

We add all the numbers together, and all the variables

2t-3

Back to the equation:

-(2t-3)


We add all the numbers together, and all the variables

3t-(2t-3)+8=0

We get rid of parentheses

3t-2t+3+8=0

We add all the numbers together, and all the variables

t+11=0

We move all terms containing t to the left, all other terms to the right

t=-11