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(3/4)(2x-1)-5=(5/4)(x-3)
We move all terms to the left:
(3/4)(2x-1)-5-((5/4)(x-3))=0
Domain of the equation: 4)(2x-1)!=0
x∈R
Domain of the equation: 4)(x-3))!=0We add all the numbers together, and all the variables
x∈R
(+3/4)(2x-1)-((+5/4)(x-3))-5=0
We multiply parentheses ..
(+6x^2+3/4*-1)-((+5/4)(x-3))-5=0
We calculate fractions
((+6x^2+3*4)(x-3)))/(-1)*4)(x-3))+4*)+()/(-1)*4)(x-3))+4*)-5=0
We calculate fractions
(((+6x^2+3*4)(x-3)))*(-1)*4)(x-3))+4*)-5)/((*(-1)*4)(x-3))+4*)-5)+(-1)*4)(x-3))+4*)+()*()/((*(-1)*4)(x-3))+4*)-5)=0
We can not solve this equation
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