-5(b+3)=b-(b-1)

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Solution for -5(b+3)=b-(b-1) equation: 



-5(b+3)=b-(b-1)

We move all terms to the left:

-5(b+3)-(b-(b-1))=0

We multiply parentheses

-5b-(b-(b-1))-15=0



We calculate terms in parentheses: -(b-(b-1)), so:

b-(b-1)

We get rid of parentheses

b-b+1

We add all the numbers together, and all the variables

1

Back to the equation:

-(1)



We add all the numbers together, and all the variables

-5b-16=0

We move all terms containing b to the left, all other terms to the right

-5b=16

b=16/-5

b=-3+1/5

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