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2(5x+3)=-5(3x-3)+3x
We move all terms to the left:
2(5x+3)-(-5(3x-3)+3x)=0
We multiply parentheses
10x-(-5(3x-3)+3x)+6=0
We calculate terms in parentheses: -(-5(3x-3)+3x), so:We get rid of parentheses
-5(3x-3)+3x
We add all the numbers together, and all the variables
3x-5(3x-3)
We multiply parentheses
3x-15x+15
We add all the numbers together, and all the variables
-12x+15
Back to the equation:
-(-12x+15)
10x+12x-15+6=0
We add all the numbers together, and all the variables
22x-9=0
We move all terms containing x to the left, all other terms to the right
22x=9
x=9/22
x=9/22
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