-5(4v-2)+4v=2(v+8)

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Solution for -5(4v-2)+4v=2(v+8) equation: 



-5(4v-2)+4v=2(v+8)

We move all terms to the left:

-5(4v-2)+4v-(2(v+8))=0

We add all the numbers together, and all the variables

4v-5(4v-2)-(2(v+8))=0

We multiply parentheses

4v-20v-(2(v+8))+10=0



We calculate terms in parentheses: -(2(v+8)), so:

2(v+8)

We multiply parentheses

2v+16

Back to the equation:

-(2v+16)



We add all the numbers together, and all the variables

-16v-(2v+16)+10=0

We get rid of parentheses

-16v-2v-16+10=0

We add all the numbers together, and all the variables

-18v-6=0

We move all terms containing v to the left, all other terms to the right

-18v=6

v=6/-18

v=-1/3

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