-5(4u-2)+7u=2(u+8)

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Solution for -5(4u-2)+7u=2(u+8) equation: 



-5(4u-2)+7u=2(u+8)

We move all terms to the left:

-5(4u-2)+7u-(2(u+8))=0

We add all the numbers together, and all the variables

7u-5(4u-2)-(2(u+8))=0

We multiply parentheses

7u-20u-(2(u+8))+10=0



We calculate terms in parentheses: -(2(u+8)), so:

2(u+8)

We multiply parentheses

2u+16

Back to the equation:

-(2u+16)



We add all the numbers together, and all the variables

-13u-(2u+16)+10=0

We get rid of parentheses

-13u-2u-16+10=0

We add all the numbers together, and all the variables

-15u-6=0

We move all terms containing u to the left, all other terms to the right

-15u=6

u=6/-15

u=-2/5

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