w(w-35)=0

Solution for w(w-35)=0 equation:

w(w-35)=0

We multiply parentheses

w^2-35w=0

a = 1; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·1·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*1}=\frac{0}{2}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*1}=\frac{70}{2}
=35
$