-5(4-4b)=32+7b

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Solution for -5(4-4b)=32+7b equation: 



-5(4-4b)=32+7b

We move all terms to the left:

-5(4-4b)-(32+7b)=0

We add all the numbers together, and all the variables

-5(-4b+4)-(7b+32)=0

We multiply parentheses

20b-(7b+32)-20=0

We get rid of parentheses

20b-7b-32-20=0

We add all the numbers together, and all the variables

13b-52=0

We move all terms containing b to the left, all other terms to the right

13b=52

b=52/13

b=4

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