Y=-2x(x-4)

Solution for Y=-2x(x-4) equation:

=-2Y(Y-4)

We move all terms to the left:

-(-2Y(Y-4))=0


We calculate terms in parentheses: -(-2Y(Y-4)), so:

-2Y(Y-4)

We multiply parentheses

-2Y^2+8Y

Back to the equation:

-(-2Y^2+8Y)


We get rid of parentheses

2Y^2-8Y=0

a = 2; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·2·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*2}=\frac{0}{4}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*2}=\frac{16}{4}
=4
$