-5(3y-7)+7y=6(y+7)

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Solution for -5(3y-7)+7y=6(y+7) equation: 



-5(3y-7)+7y=6(y+7)

We move all terms to the left:

-5(3y-7)+7y-(6(y+7))=0

We add all the numbers together, and all the variables

7y-5(3y-7)-(6(y+7))=0

We multiply parentheses

7y-15y-(6(y+7))+35=0



We calculate terms in parentheses: -(6(y+7)), so:

6(y+7)

We multiply parentheses

6y+42

Back to the equation:

-(6y+42)



We add all the numbers together, and all the variables

-8y-(6y+42)+35=0

We get rid of parentheses

-8y-6y-42+35=0

We add all the numbers together, and all the variables

-14y-7=0

We move all terms containing y to the left, all other terms to the right

-14y=7

y=7/-14

y=-1/2

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