60+3x(x+20)+3x=180

Solution for 60+3x(x+20)+3x=180 equation:

60+3x(x+20)+3x=180

We move all terms to the left:

60+3x(x+20)+3x-(180)=0

We add all the numbers together, and all the variables

3x+3x(x+20)-120=0

We multiply parentheses

3x^2+3x+60x-120=0

We add all the numbers together, and all the variables

3x^2+63x-120=0

a = 3; b = 63; c = -120;
Δ = b2-4ac
Δ = 632-4·3·(-120)
Δ = 5409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5409}=\sqrt{9*601}=\sqrt{9}*\sqrt{601}=3\sqrt{601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-3\sqrt{601}}{2*3}=\frac{-63-3\sqrt{601}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+3\sqrt{601}}{2*3}=\frac{-63+3\sqrt{601}}{6}
$